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Quote:
Originally Posted by
Hi, > I am trying to convert a 16 bit rgb value to 32 bit, however the new color generated is different from the 16 bit rgb data. Please let me know the formula to convert an 16 bit rgb data to 32 bit rgb data. Thanks!! |
You need to rigidly specify the actual bitwise format for both the
16-bit and the 32-bit form.
Your subject said the 16-bit rgb value was 565, so I have assumed it's
the binary value rrrrrggggggbbbbb. Splitting this into nybbles helps for
reading off the masks required in hexadecimal.
You said nothing about the 32-bit format. Common formats include BGR0,
RGB0, 0RGB, 0BGR. In the code below I have assumed 0RGB. Changing this
is easy, just modify the shift amounts in the last line.
unsigned long rgb16_to_rgb32(unsigned short a)
{
/* 1. Extract the red, green and blue values */
/* from rrrr rggg gggb bbbb */
unsigned long r = (a & 0xF800) >11;
unsigned long g = (a & 0x07E0) >5;
unsigned long b = (a & 0x001F);
/* 2. Convert them to 0-255 range:
There is more than one way. You can just shift them left:
to 00000000 rrrrr000 gggggg00 bbbbb000
r <<= 3;
g <<= 2;
b <<= 3;
But that means your image will be slightly dark and
off-colour as white 0xFFFF will convert to F8,FC,F8
So instead you can scale by multiply and divide: */
r = r * 255 / 31;
g = g * 255 / 63;
b = b * 255 / 31;
/* This ensures 31/31 converts to 255/255 */
/* 3. Construct your 32-bit format (this is 0RGB): */
return (r << 16) | (g << 8) | b;
/* Or for BGR0:
return (r << 8) | (g << 16) | (b << 24);
*/
}
--
Simon.
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